length of aw
minimum value that 1/tiny does not overflow
relative error requested
points and weights of the quadrature formula, aw[0...lenaw-1]
8000;
1.0e-307; function f(x) needs to be analytic over (a,infinity). relative error eps is relative error requested excluding cancellation of significant digits. i.e. eps means : (absolute error) / (integral_a^R |f(x)| dx). eps does not mean : (absolute error) / I. error message err >= 0 : normal termination. err < 0 : abnormal termination. i.e. convergent error is detected : 1. f(x) or (d/dx)^n f(x) has discontinuous points or sharp peaks over (a,infinity). you must divide the interval (a,infinity) at this points. 2. relative error of f(x) is greater than eps. </pre>
auto aw = new real[8000]; intdeoini(aw.length, tiny, eps, aw.ptr); // initialization of aw ... intdeo(f, a, omega, aw.ptr, &i, &err);
I = integral of f(x) over (a,infinity), f(x) has oscillatory factor :